[provide an image of the spectrum and any expansions you need - use Paint to crop screenshots JCB]

HNMR Spec.

The peak at 4.8 is very large and it is most likely from the solvent that was used. I looked up solvent peaks and Deuterium Oxide
has a peak at 4.8 ppm. I see a doublet between 6.6 and 6.8, and I see a doublet at about 7.6, and also a pair of doublets at 7.7. Aromatics show up between 7-8, so I think that the pair of doublets at 7.7 and the doublet at 7.6 are caused by the aromatic functional group. Coupling of the hydrogens at positions 5 and 6 on the aromatic ring may show up as 2 doublets, one for each of the 2 hydrogens, at 7.7. Actually since the pair of doublets is not symmetrical, it looks more like the second doublet is shifted slightly from the first one, which could be explained by a closer proximity to the higher electronegativity of the N atom. The only other hydrogens on the molecule are the Hs from the alcohol groups and the H on position 3 of the ring, so I don't know how to explain the other 2 doublets except maybe the doublet in the aromatic range shows the Hs from the OH groups and the doublet in the 6-7 range is the position 3 hydrogen which is then split by the adjacent OH and shifted downstream by the deshielding effect of the nitrogen atom.
[You could have used the meta coupling (about 2 Hz) to identify each peak JCB]

[no need to do CMR JCB]
CNMR Spec.