NMR of Alanine


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http://www.chemspider.com/Chemical-Structure.64234.html

Figure.1
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Figure 1. The Entire Spectrum

Figure 2.
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Figure 2. The H-atoms on the methyl group at the end form a doublet at around 1.450-1.4800 because they are H-atoms from a regular alkyl. In addition, the three H-atoms are identical so there is only a doublet formed due to the H-atom on the adjacent Carbon atom.

Figure 3.
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Figure 3. The H-atom on the second Carbon atom forms a quartet due to the three H-atoms on the adjacent Carbon atom. In addition, the H-atom is less shielded, and thereby between 3.730 and 3.800, due to the nitrogen directed bonded to its Carbon atom.

Figure 4.
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Figure 4. Because the solvent for this molecule is Deuterium Oxide, the H-atoms are quickly exchanged by the heavy water. As a result, no splitting or coupling occurs with the H-atom. In addition, the H-atom is less shielded resulting in a singlet at around 4.800. [Yes this is the spectrum of HDO JCB]

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